XSL中用count()来取得xml中某种节点的个数
list.xml
<?xml version="1.0"?>
<list>
  <application>
      <id>1</id>
    <state>1</state>
    <type>111</type>
    <title>title</title>
    <applior>applior</applior>
    <progress>
      <node>
        <state>pass</state>
        <censor>admin</censor>
      </node>
      <node>
        <state>failure</state>
        <censor>kk</censor>
      </node>
      <node>
        <state>detemind</state>
        <censor>dq</censor>
      </node>
    </progress>
    <applytime>2006-9-06</applytime>
    <deadline>
      <state>delay/ontime</state>
      <time>2006-9-12</time>
    </deadline>
  </application>
</list>
要取得<node>节点的个数可以用的方法是
<xsl:value-of disable-output-escaping="yes" select="count(//node)"/>
路径以双斜线 // 开头, 则表示选择文档中所有满足双斜线//之后规则的元素(无论层级关系)

http://www.cnblogs.com/cosy/archive/2006/09/21/510185.html